file Optimal seatings changes

24 Feb 2015 08:09 #69420 by Lönkka
Replied by Lönkka on topic Optimal seatings changes
Last tournament we had (10 plrs with 3R+F) two players were on the same table the whole game. Apparently Marko's deck shut down Tom's pretty well in all of those so he wasn't exactly happy about it.

vekn.net/forum/9-event-reports-and-twd/69254


Used the latest Archon (1,5c) for the first time and I don't reacll if I ever encountered that before with the previous versions.

Not really optimal if you play all three games in the same table as one other player... :/

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24 Feb 2015 10:44 #69425 by Ankha
Replied by Ankha on topic Optimal seatings changes

Lönkka wrote: Last tournament we had (10 plrs with 3R+F) two players were on the same table the whole game. Apparently Marko's deck shut down Tom's pretty well in all of those so he wasn't exactly happy about it.

vekn.net/forum/9-event-reports-and-twd/69254


Used the latest Archon (1,5c) for the first time and I don't reacll if I ever encountered that before with the previous versions.

Not really optimal if you play all three games in the same table as one other player... :/

Archon 1.5c contains the historical seating. The new seatings for 2R+F will be in the next archon.
I haven't started to work on 3R+F yet, but with 10 players, there is a high possiblity that you are obliged to have 2 players share the same table the whole 3 rounds.

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25 Feb 2015 14:15 #69486 by Lönkka
Replied by Lönkka on topic Optimal seatings changes
Haven't checked my old 10 player Archons if the same thing happened there or was this just an isolated case (probably not).

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26 Feb 2015 13:17 #69499 by david.tatu
Replied by david.tatu on topic Optimal seatings changes
I do not think it is possible with 2 tables and 10 players to avoid having at least 1 pair that plays all three games with each other.
If you only have two tables, each player has to play on one of them at least twice.
The only way to avoid this is more players then 10 so you get more then 2 tables.

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26 Feb 2015 14:03 - 26 Feb 2015 14:04 #69502 by Ankha
Replied by Ankha on topic Optimal seatings changes
It's impossible indeed.

R1: [1 2 3 4 5] and [6 7 8 9 10]

Consider player 1. On round 2, let's say he must be sitting with noone of the first table, so :

R2: [1 6 7 8 9] and the rest: [2 3 4 5 10]

Now consider player 6: he must sit with players others than 7, 8 and 9 so:

R3: [6 10 3 4 5] which gives as the last table [1 2 7 8 9]

So 7, 8 and 9 have shared 3 games.

Or let's say he sits with a player from the first round (eg. 2):

R2: [1 2 6 7 8] and [3 4 5 9 10]

Considering again player 6:

R3: [6 9 10 1 3] and [2 4 5 7 8]

So 7 and 8 have shared 3 games

Or let's say he sits with two players from the first round (eg. 2 and 3):

R2: [1 2 3 6 7 ] and [4 5 8 9 10]

Considering again player 6:

R3: [6 8 9 10 1] and [2 3 4 5 7] (8 and 9, 2 and 3 have shared 3 games)
or [6 8 9 10 2] and [1 3 4 5 7] (8 and 9, 3 and 4 have shared 3 games)
or [6 8 9 10 3] and [1 2 4 5 7] (8 and 9, 4 and 5 have shared 3 games)
or [6 8 9 10 4] and [1 2 3 5 7]
etc.

Or let's say he sits with three players from the first round (eg. 2, 3 and 4):

R2: [1 2 3 4 6 ] and [5 7 8 9 10]

Considering again player 6:

R3: [6 7 8 9 10] and [1 2 3 4 5] (7, 8, 9 and 10 shared 3 games)
etc.


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Last edit: 26 Feb 2015 14:04 by Ankha.

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26 Feb 2015 14:42 #69504 by a-e
Replied by a-e on topic Optimal seatings changes
Is it possible to change around seating order in a way that those two that has to sit on same table in all three games would only once be in predator/prey relations?

Because right now the three games goes like this:
game 1: A is prey of B
game 2: B is prey of A
game 3: A is grand prey of B

I think it would be better as:
game 1: A is prey of B
game 2: B is grand prey of A
game 3: A is grand prey of B

...if possible.

Marko, Prince of Helsinki

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