Tournament Finals and Seating Selection

All the work and results about optimal seatings are in this post for 2R+F: www.vekn.net/forum/generic-v-tes-discussion/67154-optimal-seatings-changes

It appears that for reasons I can't explain, the 1.5f archon is still using the old seatings instead of the latest seatings, that is for 15 players:

4 8 2 6 1 | 10 3 5 7 12 | 15 9 14 11 13

instead of

9 13 7 11 1 | 14 5 12 6 2 | 15 4 10 8 3

With the first seating, we can find 12 pairs of players that meet each other twice: 1 and 2, 1 and 4, 2 and 4, 6 and 8, 3 and 5, 7 and 10, 11 and 13, 11 and 14, 11 and 15, 13 and 14, 13 and 15, 14 and 15.
With the second seating, we can find 6 pairs of players that meet each other twice: 7 and 9, 11 and 13, 2 and 5, 12 and 14, 3 and 4, 8 and 10. That is the reason why you feel the seating is wrong.

Nevertheless, even with the second optimal seating, you will still have pairs of players. You can convince yourself by building tables where players would never meet twice. First you seat 1, 2 and 3 on different tables because we don't want them to meet twice:

1 x x x x / 2 x x x x / 3 x x x x

Now that you have seated 3 players, where do you put players 4 and 5? You can't seat them without creating two pairs of players seating twice together:

1 4 x x x / 2 5 x x x / 3 x x x x

Now do the same for players 6 - 10:

1 4 6 x x / 2 5 7 x x / 3 8 x x x

Once again, you have to create pairs:

1 4 6 x x / 2 5 7 9 x / 3 8 10 x x

And the last 5 players (11-15):

1 4 6 11 x / 2 5 7 9 12 / 3 8 10 13 x

Once again, 2 players will have to meet another player twice.

That's why you can't get below 6 pairs.

I'll create a new version of the archon that uses the latest seatings found.